X^2-18x=-2x+64

Solution for X^2-18x=-2x+64 equation:

X^2-18X=-2X+64

We move all terms to the left:

X^2-18X-(-2X+64)=0

We get rid of parentheses

X^2-18X+2X-64=0

We add all the numbers together, and all the variables

X^2-16X-64=0

a = 1; b = -16; c = -64;
Δ = b2-4ac
Δ = -162-4·1·(-64)
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16\sqrt{2}}{2*1}=\frac{16-16\sqrt{2}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16\sqrt{2}}{2*1}=\frac{16+16\sqrt{2}}{2}
$